Simplified method of feed pipe balancing at pneumatic reactor feed

When an industrial process/a reactor is to be pneumatically fed with a solid material via several, simultaneously supplied feed points, one of the requirements is uniform distribution of the solids mass flows. To enable a precise calculation of the individual flows and total flows, numerous parameters are required.

1 Introduction

Various industrial processes are supplied with solid material via parallel pneumatic conveying pipes from several injection points. Normally, it is required that the individual solid material flows are distributed uniformly to the different injection points. The efficiency of this uniform distribution has to be guaranteed. One example for such a process is the feeding of coal dust into blast furnaces for hot metal production. Depending on the capacity of the furnace, the coal dust is pneumatically fed through up to around 40 individual lances arranged around the periphery of the...

1 Introduction

Various industrial processes are supplied with solid material via parallel pneumatic conveying pipes from several injection points. Normally, it is required that the individual solid material flows are distributed uniformly to the different injection points. The efficiency of this uniform distribution has to be guaranteed. One example for such a process is the feeding of coal dust into blast furnaces for hot metal production. Depending on the capacity of the furnace, the coal dust is pneumatically fed through up to around 40 individual lances arranged around the periphery of the furnace/opening of the tuyère. It has to be pneumatically injected as a continuous flow against the furnace pressure (which can be several bar).

Two possible systems for fulfilling this requirement are schematically depicted in Fig. 1: Section 1a shows a distributor, which splits the pneumatically delivered gas/solids mixture M·tot = (M·F + M·S) to N outgoing parallel pipes, while section 1b shows the distribution to the N pipes in a fluidized/suitably aerated pressure vessel. Although it is in principle also possible to feed the conveying gas/solids mixture via individual pipes, this quickly leads to substantial capital cost when a larger number of pipes is involved. In the following, it is assumed that the individual parallel pipes all have an identical inside diameter DR.

As can be seen from Fig. 1, the same pressure difference pD,C = (pD – pC) exists in all the parallel pipes, with: pD being the pressure in the distributor/dispatcher and  being the pressure in the reactor/ receiver. In view of the fact that there can be differences in both the lengths and the spatial routing of the pipes to their infeeding points at the reactor, so that their specific flow resistances also differ, there are different mass flows M·tot,j of the conveyed gas-solids mixture in the individual pipes. The smallest mass flow passes through the pipe with the largest specific resistance, and vice versa. For this reason, uniform distribution has to be imposed by installing additional conveying pipe elements – straight pipe sections, bends etc. – in the various pipes, i.e. by equalizing the individual specific resistances Fig. 2 shows the practical implementation of such an equalization station for feeding a blast furnace.

2 Uniform distribution through feed pipe balancing

The system under consideration here has to assure uniform distribution of a solids mass flow M·S to N parallel individual pipes. The thereby occurring conveying gas distribution is unclear. However, it must be known for the purpose of conveying system calculation and is also of significance for cases in which the gas is simultaneously used as a reaction partner, e.g. in systems supplying coal dust burners with air. For the further considerations it is assumed that when the solid material is uniformly distributed the gas is also uniformly distributed.

The following equations:  = (M·S/M·F) = j = (M·S,j/M·F,j) = const. and Mtot,j = (M·tot/N) = const. thus apply for the  parallel pipes. This approach appears plausible because the gas has a higher velocity than the solid material and thus flows quasi through a column of material, whose high resistance forces a uniform distribution to all the pipes.

2.1 Precise calculation
For designing a distribution system for feeding a reactor, CPP uses the program „Regsi“. To ensure correct calculation of the two-phase flow through the parallel individual pipes, this program requires the sequential entry of all the piping elements of all conveying routes from the distributor to the reactor, i.e. the lengths, positions and spatial orientation of straight pipe sections, the bends including their deflection angles and radii, the valves including their opening cross-sections etc. all have to be specified. The program then uses the known pressures (pD,pC) and the relevant characteristic values of the gas and bulk material to calculate the solids and gas mass flows (M·S,j, M·F,j) occurring in the individual pipes. On the basis of these data the required feed pipe balancing can be carried out by entering diverse additional piping elements. In order to take account of the real boundary and execution conditions of the respective system, the specification of type and position of these elements is done manually. The subsequent computation results in the new distribution, which can then be continuously improved step by step by means of further entries.

The computing program contains all the equations that are required for calculating the individual elements and their interactions. These equations have been checked, adapted and improved in the course of comprehensive trials in the CPP test plant facility. The measured and the computed solid material distribution precisions differ by less than RF = ± 2 % by mass. A computational balancing to RF < ± 0.5% by mass does not make sense because of the occurring manufacturing inaccuracies, pipe tolerances etc.. Details are provided in [1-4].

From the foregoing, it is understandable that usage of the program is time-consuming. The following sections will therefore propose a simplified method of feed pipe balancing.

2.2 Calculation with equivalent lengths
The pressure drop ph of a gas/solid material flow through a straight, horizontal pipe of length  can be described through the approach:
ph = (F +  + s) LR,h · F,h · u2F (1)
                             DR      2
where: F = drag coefficient of the gas,

s  = drag coefficient of the solid material,

μ = (M·S/M·F), loading, mass flow ratio of solid ­material : gas,

F,h = mean gas density,

uF = mean gas velocity.

Under consideration of the continuity equation, substitution of the loading by the mass flows of gas and solid material, and definition of the horizontal two-phase flow,
tot = F + S → tot ·  = F +  · S (2)
               
is derived from equation (1):

ph = tot · 1 ·    LR,h    ·  M·S · M·F (3)
                2  DR · A2R        F,h
with: AR = ( π4  · D 2R), pipe cross-section area.
The total pressure drop ptot of a conveying route is equal to the sum of the pressure drops of the individual piping elements , i.e. it is composed of a series of resistances. They are described by means of different calculation approaches which contain not only the type of the element but also its position along the length of the conveying pipe. In the following, the resultant complex conveying pipe calculation will firstly be simplified, and the result will then be employed for the feed pipe balancing. For this purpose, the pressure drop of the respective piping element is converted to that of a straight, horizontal pipe section of equivalent length that produces the same pressure drop. This procedure is depicted on the basis of a single pipe bend with any desired deflection angle . Its pressure drop amounts to:
pb = Kb · Cb · F,b · u2F,b = Kb · Cb · M·S · M·F (4)
                                                A2R           F,b
   
The factor Kb describes the relationship with b and with the sliding friction coefficient b between the bulk material and the wall of the bend. It can be evaluated with [5]:

Kb = 1 – exp (–b · π ·  b    ) (5)

                         180°   

For 90° bends in steel pipes, equation (5) produces: Kb =~ 0,50. Comparison with an equivalent horizontal pipe section then produces:

pb = tot · 1 ·    Läq,b   · M·S · M·F = Kb · Cb · M·S · M·F (3)
                2  DR · A2R        F,h             A2R          F,b 
With Cb = C–  and F,h = F,b = F, the equivalent bend length is found to be
Läq,b  = Kb ·  2 · C– · DR  (7)
                     tot          
with: F = the gas density at mean pressure  = ½ · (pD + pC) in the conveying pipe, C–, Cb = (us/uF), velocity ratios of solid/gas.

The equivalent total length of xb identical bends, e.g. of 90° bends, then amounts to (xb · Läq,b).

Table 1 presents the associated pressure drop valuations [5] and the derived equivalent lengths Läq,i, by way of example for different conveying pipe elements and piping situations. The Läq,i values are determined with a solids/gas velocity ratio averaged over the respective conveying route C– and a mean gas density F instead of the local values (Ci, F,i). This simplifies the calculation and does not cause any significant reduction in precision when balancing the feed pipes: At given pressures (pD, pC) and the aimed-at uniform distribution, an identical mean gas density and an (approximately) identical velocity profile occurs in all parallel pipes.

The pressure drop equation of an individual pipe is simplified by means of the described method to:

pD,C = tot · 1 ·  ∑Läq,i    · M·S · M·F (8)
                  2    DR · A2R        F
For feed pipe balancing, the equivalent total lengths ∑Läq,i = Läq,tot of the j = 1 ··∙ N parallel pipes are first determined. The pipe with the greatest equivalent length, e.g. Läq,tot,N, carries the smallest mass flow M·tot,N or M·S,N and must therefore be dimensioned for the required throughput. The throughput rates of the equivalent shorter pipes are higher, M·tot,jN > M·tot,N , and have to be reduced to the required value by adjusting the equivalent lengths. For this purpose, the differences Läq,j = (Läq,tot,N – Läq,tot,jN) are generated and then converted with the aid of the equations in Table 1 into real pipe elements with corresponding Läq,j values. The installation position of these pipe elements along the respective pipe can be flexibly determined.
2.3 Application example
Fig. 3a shows a pressure vessel system with N = 4 outgoing conveying pipes for continuously feeding a reactor with a total of M·S = 8,0 t–h of coal dust via specified infeeding points. Uniform distribution of the coal dust mass flows is required, i.e. M·S,j = 2,0 t–h. Nitrogen is used as the conveying gas; M·S = 8,0 kg—h. Pressure in the dispatcher: pD = 2,25 bar (abs); pressure in the reactor: pD = 1,0 bar (abs); pD,C = –1,25 bar (abs). Steel piping, (ø 33,7 x 2,6) mm, DR = 28,5 mm, AR = 0,63794 · 10-3 m2. Design temperature: 20°C. Other data: tot = 0,010, C– = 0,90, F = 1,868 kg/m3, b = 0,44.

Due to the structural situation, the piping route depicted in Fig. 3a is initially planned. 90° bends with a radius of Rb = 0,5 m are to be used. Table 2 contains the equivalent lengths calculated for this layout and also the solids mass flows M·S,j bar occurring at a pressure difference of pD,C = 1,25 bar. The M·S,j values for this case and in the following text were calculated with the CPP design program for pneumatic conveying systems. This program employs an alternative calculation model [6], which is based on the real conveying pipe route, and is used for additional substantiation of the results.

The differences Läq,j in the equivalent lengths result in unacceptably large deviations of the solids mass flows M·S,j from the required value M·S,4 = 2,0 t/h. Feed pipe balancing is therefore necessary. In this case, the Läq,j≠4 values are converted into 90° bends (Läq,b = 2,565 m) and straight, horizontal pipe sections in accordance with possible alternative piping routes. Fig. 3b shows a design variant and Table 3 presents the associated operating data for a complete feed pipe balancing.

In order to achieve Läq,j = 0, the selected distances (a, b), compare Fig. 3b, must be a =~ 5,218 m and b =~ 7,935 m. However, in practice such precision cannot be achieved, so that residual lengths Läq,j ≠ 0 will always remain. Table 4 shows the effects of different Läq,j residual lengths on the distribution precision by example of pipe 1. The  values were again determined with the CPP design program for pneumatic conveying systems.

The solids mass flows M·S,j calculated with the equivalent length model – equation (8) – and with the CPP design program for pneumatic conveying systems differ slightly. The mass flows calculated with the CPP design program are more accurate, because the program takes account of the real positions of the different pipe elements along the conveying routes. However, the effects on the feed pipe balancing are negligible.

3 Load behaviour

Changes in loading (M·S, F) generally lead to change in the pressure difference pD,C. However, the approaches to calculation of the equivalent lengths Läq,l in Table 1 indicate that once a uniform distribution is set, it is maintained independently of the current load condition if all the conveying pipe elements employed for the feed pipe balancing correspond to equations (9) to (12). The equivalent length  describing the lifting of the gas/solids mixture – equation (13) – is influenced by the conveying gas mass flow M·F: A decrease in the gas throughput rate increases the quantity of bulk material currently present in the vertical pipe, thereby increasing the lifting pressure drop, and therefore requiring a greater equivalent length and vice versa. As the lifting and frictional losses occur simultaneously, vertical pipe sections negatively affect the distribution precision in the case of changes in M·F. Changes in the solids mass flow M·S do not have any effect.

The equivalent length Läq,o of a throttle valve or of a control valve can be calculated using equation (14), Table 1. It can be seen that changes in the solids mass flow M·S and in the gas mass flow M·F influence the current length of Läq,o. In order to maintain a uniform distribution despite any occurring changes in load, the drag coefficient (Ao)  of the valve would have to be adapted to suit the respective conditions by adjusting the cross-section of the opening Ao. However, according to equation (14) one exception to the above rule is a change in load during which the ratio (M·S/M·F) = μ is kept constant, because this does not change Läq,o. Other approaches to describing the pressure drop behaviour of valves produce comparable results.

The above considerations imply that it is best to balance the feed piping by installing straight, horizontal piping elements and/or pipe bends with any desired deflection angle.

The described process can be used for the designing of reactor feeding systems with a specified, fixed unequal distribution of the solids mass flows M·S,j. Furthermore, it is possible to compensate for any locally fixed unequal distribution of the reactor pressure pC.

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